Differential Equations - Related Rate

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SUMMARY

The discussion centers on the mathematical modeling of a raindrop's evaporation using differential equations. It establishes that the mass loss rate of a spherical raindrop is proportional to its surface area, leading to the equation dm/dt = -k * 4 * π * r², where k is a constant. The participant seeks to demonstrate that the rate of change of the radius, dr/dt, is constant, ultimately leading to the solution r(t) = c1 * t + c2 after integration. The conversation highlights the relationship between mass, density, and volume in the context of spherical geometry.

PREREQUISITES
  • Understanding of differential equations and their applications
  • Familiarity with the geometry of spheres, particularly surface area and volume calculations
  • Knowledge of integration techniques in calculus
  • Concept of proportionality in mathematical modeling
NEXT STEPS
  • Study the derivation of the mass loss equation for spherical objects
  • Explore the implications of constant rates of change in differential equations
  • Learn about the relationship between surface area and volume in three-dimensional shapes
  • Investigate real-world applications of related rates in physics and engineering
USEFUL FOR

Students studying calculus, particularly those focusing on differential equations and related rates, as well as educators seeking to explain the concepts of mass loss in spherical objects.

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Homework Statement



Assume that a typical raindrop is spherical. Starting at some time, which we designate as t = 0, the raindrop of radius r sub o falls from rest from a cloud and begins to evaporate.

a) If it is assumed that a raindrop evaporates in such a manner that its shape remains spherical, then it also makes sense to assume that the rate at which the raindrop evaporates - that is, the rate at which it loses mass - is proportional to its surface area. Show that this latter assumption implies that the rate at which the radius r of the raindrop decreases is a constant. Find r(t).

There is a b part but I think I understand how that is done.

Homework Equations


Surface Area of a Sphere is 4*pi*r2

The Attempt at a Solution


-d(m)/dt is proportional to 4*pi*r2

Therefore

dm/dt = -k*4*pi*r2

Where k is a constant to remove the proportionality.

if dr/dt = constant represented by c

then after we integrate that equation we get

r(t) = c1*t + c2

After that I did some really weird math that I don't think is possible. Any ideas?
 
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Mass is density (rho) times volume. So you have (rho*(4/3)*pi*r(t)^3)'=k*4*pi*r(t)^2. Can you show that implies r'(t) is constant?
 

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