Differential equations separation of variables

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SUMMARY

The forum discussion focuses on solving the differential equation \( \frac{xdv}{dx} = \frac{1-4v^2}{3v} \) using the method of separation of variables. The correct separation leads to the equation \( \frac{dx}{x} = \frac{3v}{1-4v^2} dv \). Participants confirm that after proper separation, integration is straightforward, and applying initial conditions is essential for finding the specific solution.

PREREQUISITES
  • Understanding of differential equations
  • Familiarity with the separation of variables technique
  • Basic integration skills
  • Knowledge of initial conditions in differential equations
NEXT STEPS
  • Study the method of separation of variables in depth
  • Learn about integrating functions involving rational expressions
  • Explore initial value problems in differential equations
  • Practice solving more complex differential equations
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Mathematics students, educators, and anyone interested in solving differential equations using separation of variables will benefit from this discussion.

EP
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xdv/dx=(1-4v^2)/3v

I used separation of variables to get

x/dx=(1-4v^2)/3v dv

I'm not sure if that's even right.

But if it is right, how do I integrate that?
 
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Your Separation of variables looks good, now a simple substitution finishes the job.
 
EP said:
xdv/dx=(1-4v^2)/3v

I used separation of variables to get

x/dx=(1-4v^2)/3v dv

I'm not sure if that's even right.

But if it is right, how do I integrate that?
You made a slight mistake with the variable separation--- you can't have dx in the denominator! (Atleast, I've learned not to do it)
You should have done:
xdv = (1-4v^2)/3v dx
dx/x = 3v/(1-4v^2) dv
Integration from there is pretty simple... apply your initial conditions. :)
 

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