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dy/dx = (3x + 2y)/(3x + 2y + 2) , y(-1) = -1

I need to use substitution and use the formulas:

du/dx = A + B(dy/dx)

dy/dx = (1/B)*(du/dx - A)

Let u = 3x + 2y then du/dx = 3 + 2(dy/dx)

therefore A = 3, B = 2

Pluging it into the formula gives me:

(1/2)*(du/dx - 3) = (3x + 2y)/(3x + 2y + 2)

Now I would need to separate the equation and integrate both sides, replace back what I substituted and solve the IVP where x = -1 and y = -1 to find the constant.

How do i make this equation a separable equation?