Differential form of gauss's law.

Click For Summary
SUMMARY

The discussion centers on the differential form of Gauss's Law, specifically the relationship between electric field divergence and charge density. The equation div E = ρ/ε₀ is established, where ρ represents charge density and ε₀ is the permittivity of free space. Participants clarify that charge density is defined as ρ = lim(ΔV → 0) (ΔQ/ΔV), and the divergence of the electric field is linked to the net flow of the electric field across a boundary. The conversation also touches on the implications of electric field divergence away from point charges, suggesting a deeper exploration of Coulomb's law and the Dirac delta function.

PREREQUISITES
  • Understanding of Gauss's Law and its applications in electromagnetism.
  • Familiarity with the concept of electric field divergence.
  • Knowledge of charge density and its mathematical definition.
  • Basic grasp of vector calculus, particularly the divergence operator.
NEXT STEPS
  • Study the derivation of Gauss's Law in differential form.
  • Learn about the implications of electric field divergence in various charge distributions.
  • Examine Coulomb's law and its relationship to electric field lines.
  • Research the Dirac delta function and its applications in physics, particularly in electromagnetism.
USEFUL FOR

Students and professionals in physics, particularly those focusing on electromagnetism, as well as educators seeking to clarify the concepts of electric field divergence and charge density.

bmrick
Messages
44
Reaction score
0
I don't understand what charge density is meant in the equation: div E = constant times charge density. I have the derivation in front of me and the last step follows from accepting that the rate of change of the integral of the field divergence per change in volume is the same as the rate of change of the integral of charge density per that same change in volume, and as such the divergence of an e field is one over permitivity times the... charge density at that point? What does this mean? How does it account for divergence of an e field away from point charges?
 
Physics news on Phys.org
Charge density is defined as the charge in a small volume divided by the volume. More exactly: the charge density at a point P is\rho=\lim_{\Delta V \rightarrow 0}\frac{\Delta Q}{\Delta V}

On the other hand, the divergence of a vector-vector function is defined as
Definition of divergence

More rigorously, the divergence of a vector field F at a point p is defined as the limit of the net flow of F across the smooth boundary of a three-dimensional region V divided by the volume of V as V shrinks to p.
See http://en.wikipedia.org/wiki/Divergence
So the divergence of E integrated for a volume V surrounding the point P is equal to the surface integral of the normal component of E enclosing the volume, which is equal to ##Q/\epsilon _0##, Q being the charge of the volume, according to Gauss' Law. At the limit of ## \Delta V \rightarrow 0##,
## div E = \rho/\epsilon_0##

ehild
 
bmrick said:
How does it account for divergence of an e field away from point charges?

Are you thinking about the spreading-out of electric field lines from a point charge? It might be instructive to calculate the divergence explicitly for the Coulomb's-law field of a point charge at the origin: \vec E = k \frac {\hat r}{|\vec r|^2} = k \frac {\vec r}{|\vec r|^3} = k \frac {x \hat i + y \hat j + z \hat k}{(x^2 + y^2 + z^2)^{3/2}} Then consider what happens at ##\vec r = 0## and read up on the Dirac delta "function" if necessary (e.g. in Griffiths, section 1.5).
 
  • Like
Likes   Reactions: vanhees71

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 29 ·
Replies
29
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 30 ·
2
Replies
30
Views
3K