Differentiate e^fx: Solving 2xe^(2x)

[CrossFit415]

f(x)= xe^(2x)

So I applied the product rule
(f • g) = x • e(^2x) + e^(2x) • 1
= xe^(2x) + e^(2x)
=2xe^(2x)

And got this as my final answer.

Would I need to use chain rule? Did I do this correctly?

 

[Ivan92]

f(x)= xe^(2x)


(f • g)' = x • e(^2x) + e^(2x) • 1

You forgot to take the derivative of e^(2x)