equation for derivative of n product
A similar question came to me while finding the derivative of a function equal to the product of three differentiable functions here is my generalization to a function equal to an infinite product:
Let g_{n} = \prod^n_{k=1}f_{k} and assume that f'_n exists. Then by the product rule of differentiation and some clever factoring
g'_n = (\prod^n_{k=1}f_{k})\sum^n_{j=1}\frac{f'_j}{f_j}
which is even more simply written as
g'_{n} = g_{n}\sum^n_{j=1}\frac{f'_j}{f_j}.
To see how I get to this generalization I will work out the derivative for
g_{3} = \prod^3_{k=1}f_{k}=f_1f_2f_3.
First,
g'_{3}= f_2f_3f'_1 + f_1(f_2f_3)'= f_2f_3f'_1 + f_1(f_2f'_3+f_3f'_2)= f_2f_3f'_1+f_1f_2f'_3+f_1f_3f'_2
Then noticing the relationship between this form and the original equation,
g'_3=\frac{g_3}{f_1}f'_1+\frac{g_3}{f_2}f'_2+\frac{g_3}{f_3}f'_3= g_3(\frac{f'_1}{f_1}+\frac{f'_2}{f_2}+\frac{f'_3}{f_3})
which is what the general function predicted,
g'_3=g_3\sum^3_{j=1}\frac{f'_j}{f_j}
I know that this statement is true for specific values of n, but I’m not sure what features this function has when g is an infinite product of differentiable functions. I hope that this helps with the question at hand.