Differentiate the given function using implicit.

[1irishman]

Homework Statement

2x^3 - 8xy + y^2 = 1

Homework Equations

The Attempt at a Solution

d2x^3/dx - d8xy/dx + dy^2/dx = d1/dx
6x^2 -8(y) + dy/dx(-8x) + 2y(dy/dx) = 0
6x^2 - 8y -8x(dy/dx) + 2y(dy/dx) = 0 I am stuck and can't seem to go further. Someone help?

 

[RK1992]

youve answered the question - youve differentiated what you were given.

if you want to find dy/dx explicitly, you can try factorizing to get there.

 

[1irishman]

Homework Statement

2x^3 - 8xy + y^2 = 1

Homework Equations

The Attempt at a Solution

d2x^3/dx - d8xy/dx + dy^2/dx = d1/dx
6x^2 -8(y) + dy/dx(-8x) + 2y(dy/dx) = 0
6x^2 - 8y -8x(dy/dx) + 2y(dy/dx) = 0 I am stuck and can't seem to go further. Someone help?


[/Qdy/dx = 8y-6x^2/2y-8x=4y-3x^2/y-4x
okay got it thank you. i skipped a couple of steps
UOTE]