# Differentiation question

1. Jan 4, 2008

### david18

"the equation of a curve is x^2y=x-6 (x^2y is x squared times y)

The normal of the curve at the point where x=-2 meets the x axis at p.

Find the coordinates of P"

The method I used was to find y by rearranging the given equation and differentiate it.
This gave me f ' (x)= 1+12x^-3

Then I subbed x=-2 in so that I could find the gradient of the tangent at that point. It worked out as -1/2, so then the gradient of the normal would be 2.

After finding the equation of the line and making y=0, I got the wrong answer: x=-1 and y=0

apparently the answer is (3/2, 0)

any help would be appreciated

2. Jan 4, 2008