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- Thread starter Shoney45
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- #1

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- #2

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let u=x and dv=e^(-x(1+y))

then,

du=1

and v= [e^(-x(1+y))]/(-(1+y))

I think it should work

if you want let

u=e^(-x(1+y))

du= -(1+y)*e^(-x(1+y))

you treat y as a constant and x as a variable

(I am assuming you want to integrate in terms of x)

- #3

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Alrighty then - I'll get to work. Thanks for the direction.

- #4

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I think it's possible to solve it in terms of x

let u=x and dv=e^(-x(1+y))

then,

du=1

and v= [e^(-x(1+y))]/(-(1+y))

Actually du = dx, also dv=e^(-x(1+y))dx

You can simplify this problem, by performing a w substitution at the beginning ie. consider w = -x*(1+y). It will make the integration by parts less of a headache.

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