Diffrentiation of natural logs (ln)

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Homework Help Overview

The problem involves differentiating the function (ln(5x))^1/5 with respect to x, which falls under the subject area of calculus, specifically focusing on differentiation techniques and the application of the chain rule.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the differentiation process, with one original poster expressing uncertainty about their result and suggesting an alternative answer. Others question the correctness of the proposed answers and emphasize the need to apply the chain rule correctly. There is also a discussion about the nature of the answer, whether it should be a function or a numerical value.

Discussion Status

The discussion is ongoing, with participants providing guidance on the differentiation process and exploring different interpretations of the derivative. There is a focus on clarifying the application of the chain rule and the correct form of the derivative.

Contextual Notes

Some participants express confusion regarding the expected form of the answer, debating whether it should be a numerical value or a function. The original poster's initial differentiation attempt is also questioned for its accuracy.

chanella35
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the question is: differentiate wiith repsect to x:

(ln(5x))^1/5

i differentiated and got :

1/5ln(5x)

y'=1/5x


I don't think this is correct. The answer should be ln5/5.

Can anyone help me?

chanella
 
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chanella35 said:
the question is: differentiate wiith repsect to x:

(ln(5x))^1/5

i differentiated and got :

1/5ln(5x)

y'=1/5xI don't think this is correct. The answer should be ln5/5.

Can anyone help me?

chanella
That's not right. The answer shouldn't be ln5/5, because that's a number. The answer should be a function.

Use the chain rule: power to the front, subtract 1, multiply by the derivative of what's inside the bracket.
 
logarithmic said:
That's not right. The answer shouldn't be ln5/5, because that's a number. The answer should be a function.

Use the chain rule: power to the front, subtract 1, multiply by the derivative of what's inside the bracket.

So the answer would be;

y'=1/5 (5)(ln5x)^(1/5-1)

y'= (ln5x)^-4/5

is this right??

Thanks for helping :)
 
chanella35 said:
So the answer would be;

y'=1/5 (5)(ln5x)^(1/5-1)

y'= (ln5x)^-4/5

is this right??

Thanks for helping :)

Almost. The derivative of ln(f(x)) is f'(x)/f(x), so the derivative of ln(5x) is 5/(5x) = 1/x.

So replacing (5) with (1/x), then simplifying is the correct answer.
 

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