(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

what is the potential 18 cm from a dipole moment 2.6nCm at

a) 42 deg to axis

b) on the perpendicular bisector

note: dipole separation << 18cm

2. Relevant equations

electric dipole moment, p = qd where q is charge, d is distance

electric potential for point charge, V = kq/r where k is 9*10^9 and r is distance

3. The attempt at a solution

a) 42 degrees

i think my eq may be wrong, but...

p =qd sin (theta) where theta = 42deg

so q = p/dsin(theta)

so V = [k(p/dsin(theta)]/r

so using sin(42) i got V = 1.08 kV and using cos(42) i got V = 0.971 kV --> both incorrect

i'm guessing my eq for electric dipole moment is wrong, i was thinking along the lines of the torque eq, rFsin(theta)

b) not attempted yet, but what is the perpendicular bisector? any tips much appreciated

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# Homework Help: Dipole moment electric potential

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