Directional derivative with angle

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SUMMARY

The forum discussion centers on calculating the directional derivative of the function f(x,y,z) = sin(5x) + ln(y² + 1) + z³ at the point (0,1,3) from the direction of the vector (1,1,0). Participants clarify that the gradient should be evaluated at the starting point (1,1,0) and that the direction vector to arrive at the target point (0,1,3) is (-1,0,3). The correct unit vector is derived as [(-1,0,3)]/√10, leading to the final result of the directional derivative being 76/√10 after performing the dot product with the gradient.

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  • #31
That's all the question provides, pi/4
 
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  • #32
This is a conceptual question as it says "of a vector" so that means of any normal vector \vec{n}\cdot\vec{T}=0 (orthogonality condition)
 
  • #33
hmm..are you sure?
 
  • #34
djeitnstine said:
This is a conceptual question as it says "of a vector" so that means of any normal vector \vec{n}\cdot\vec{T}=0 (orthogonality condition)

I think I see what djeitnstine is saying. The directional derivative is grad(f).n. You also know an expression for the dot product in terms of the lengths of the vectors and the angle between them, I hope.
 
  • #35
-EquinoX- said:
Say the question is like this:

Find the directional derivative of f(x,y,z) = xy + z2 at the point(2,2,3) in the direction of a vector making an angle of pi/4 with gradf (2,2,3). Give an exact answer.

Therefore my first step is to find the gradient and I need to something similar to what I've done with this question, however.. how do I find the vector if all I know is pi/4
One major problem with this is that there are an infinite number of vectors "in the direction of a vector making an angle of pi/4 with gradf (2,2,3)". That is NOT a unique direction.
 
  • #36
-EquinoX- said:
hmm..are you sure?

Yes I'm sure, I've done it quite a number of times.
 

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