Directional Derivative of Lake Depth at Point (-1, 2) in Direction (4, 1)

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SUMMARY

The discussion focuses on calculating the directional derivative of lake depth at the point (-1, 2) using the function D(x, y) = 100 - 4x² - y². The user needed to determine whether the water is getting deeper or shallower while sailing in the direction of the vector (4, 1). The solution involves computing the gradient of D, evaluating it at the specified point, and then taking the dot product with the unit vector of the direction. The correct answer for the directional derivative is 28/sqrt(17), which was initially miscalculated due to a simple arithmetic error.

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  • Familiarity with the function D(x, y) = 100 - 4x² - y²
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RaulTheUCSCSlug
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Having a melt down as I have done this problem twice now and my exam is tomorrow and I can't seem to figure it out anymore... ugh. 1. Homework Statement
The depth of a lake at the point on the surface with coordinates (x, y ) is given by D(x, y ) = 100−4x 2 −y 2 . a) If a boat at the point (−1, 2) is sailing in the direction 4~i +~j, is the water getting deeper or shallower ?

Homework Equations


I know that I need to use the gradient and I am going to need to have the direction scaled to a unit vector.

The Attempt at a Solution


So I took the gradient of D(x,y), plugged in (-1,2) then dotted it with the unit vector of (4,1) the answer is supposed to be 28/sqrt(17) and I can't seem to get that answer.
 
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never mind, I just kept doing the unit vector wrong. Simple arithmetic mistake.
 

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