Discovering the Minimum Value of Tan(x^2+2x) without a Calculator

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SUMMARY

The discussion centers on finding the minimum value of the function tan(x^2 + 2x) without using a calculator. Participants confirm that while there is no absolute minimum, a relative minimum can be identified using calculus techniques. The derivative of the function, sec^2(x^2 + 2x) * (2x + 2), is crucial for determining the critical points. The conversation emphasizes the importance of correctly applying calculus to solve the problem effectively.

PREREQUISITES
  • Understanding of calculus, specifically derivatives
  • Familiarity with trigonometric functions, particularly tangent
  • Knowledge of critical points and relative minima
  • Ability to perform algebraic manipulation of functions
NEXT STEPS
  • Study the application of derivatives in finding relative minima
  • Learn about the properties of the tangent function and its behavior
  • Explore the concept of critical points in calculus
  • Investigate the implications of secant and secant squared functions in calculus
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Students and professionals in mathematics, particularly those studying calculus, as well as anyone interested in optimizing trigonometric functions without computational tools.

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Find where the min value will occur of tan(x^2+2x)

is there a way to do this without a calculator because I can't seem to figure it out without it. Also I'm not sure what the interval should be.
 
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Punkyc7 said:
Find where the min value will occur of tan(x^2+2x)

is there a way to do this without a calculator because I can't seem to figure it out without it. Also I'm not sure what the interval should be.

There's always Calculus!

What's the derivative of tan(x2+2x) ?

BTW: There is no absolute minimum.

There is one relative minimum which can be easily found using the derivative.
 
sec^2(x^2+2x)*(2x+2)... I got it now. Thanks, I was messing up my line check.
 

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