Discovering the Type of Waveform from a Fourier Series | Homework Help

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Discussion Overview

The discussion revolves around identifying the type of waveform generated by a given Fourier series representation. Participants explore the implications of the series components and their contributions to the overall waveform, with a focus on understanding the mathematical formulation and its physical interpretation.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant presents a Fourier series representation and asks what type of waveform it produces.
  • Another participant suggests that Fourier series typically use odd harmonics to create a sawtooth waveform, questioning the validity of the presented series.
  • A participant challenges the source of the waveform components, seeking clarification on the input provided.
  • Concerns are raised about the validity of the inputs, with a suggestion that they would lead to an increasing voltage rather than a proper waveform representation.
  • One participant references a Wikipedia example of a sawtooth waveform, noting the difference in coefficients compared to the presented series.
  • Another participant clarifies that the '5' in the series represents the peak amplitude, which is relevant for calculating Fourier coefficients.

Areas of Agreement / Disagreement

Participants express differing views on the validity of the waveform inputs and their implications. There is no consensus on the type of waveform produced by the given Fourier series, and the discussion remains unresolved.

Contextual Notes

Participants highlight potential limitations in the understanding of Fourier series, particularly regarding the treatment of amplitudes and the implications of using different harmonics. The discussion reflects uncertainty about the mathematical formulation and its physical representation.

suv79
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Homework Statement



what type of waveform would this make ?

Homework Equations



V(t)=2/π(sin(ωt)+1/2sin(2ωt)+1/3sin(3ωt)+1/4sin(4ωt)+...)

5sin(ωt)+5sin(2ωt)+5sin(3ωt)+5sin(4ωt)...

The Attempt at a Solution

 

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all that I have read about Fourier series, it uses odd number for 'n' to make an sawtooth waveform,

5sin(ωt)+5sin(2ωt)+5sin(3ωt)+5sin(4ωt)... this is not add together as it is increasing the voltage ?
 
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Where did you come up with

suv79 said:
5sin(ωt)+5sin(2ωt)+5sin(3ωt)+5sin(4ωt)
 
that is from the input, see the 2nd attached.
i don't understand what waveform the input will be making.
 
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Those inputs I don't think are valid, cause you are right as they stand they'd keep adding.
Generally with Fourier series as the frequency of the component goes up the scalar goes down.
Take a look at http://en.wikipedia.org/wiki/Fourier_series
example 1 is actually the sawtooth waveform. You'll notice that is not 5 as you have in your example but rather 2*(-1)^{n+1}\over(\pi*n)
 
the 5 is Peak amplitude.
 
Well then it would be multiplied by 5. The peak amplitude is generally taken into account when you do the integral to calculate Bn & An
 

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