Displacement of Underdamped Oscillation: Maximum and Minimum Occurrence?

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SUMMARY

The discussion focuses on the displacement of underdamped oscillations, specifically addressing the timing of local maxima and minima in relation to the equilibrium point. The equations provided include the displacement formula x = e^{-\frac{ct}{2m}}(A cos(wt) + B sin(wt)) and the angular frequency w = \frac{\sqrt{4mk - c^2}}{2m}. It is established that local extrema do not occur halfway between equilibrium crossings, as maxima and minima occur at specific intervals defined by the angular frequency. The participant also seeks clarification on estimating parameters c, m, and k from a general equation.

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Homework Statement


Show that the local maximum or minimum for the displacement of an underdamped oscillation does not occur halfway between the times at which the mass passes its equilibrium point.

Homework Equations


[tex]x = e^{-\frac{ct}{2m}}(A cos(wt) + B sin(wt))[/tex]
[tex]x = K e^{-\frac{ct}{2m}} sin(wt + P)[/tex]

[tex]T = \frac{2\pi}{w}[/tex]

w = angular frequency = [tex]\frac{\sqrt{4mk - c^2}}{2m}[/tex]
Because the system is underdamped, 4mk > c^2

T = period

The Attempt at a Solution


I said [tex]sin(wt + P)[/tex] attains its maximum when [tex]wt + P = (4k + 1)\frac{\pi}{2}[/tex] and min when [tex]wt + P = (2k + 1)\frac{\pi}{2}[/tex]
Likewise, it crosses the equilibrium when [tex]wt + P = k\pi[/tex].

Thus the period for a pass by equilibrium is simply [tex]\frac{pi}{w}[/tex]

So I did [tex]k\pi + \frac{\pi}{2w} = (2k + \frac{1}{w})\frac{\pi}{2}[/tex]
But this does cross a min if w = 1... where did I go wrong?
 
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I also have a follow up question. Given a general equation, how do I estimate the parameters c, m, k
 
Sorry for bumping this, but I'm actually not even sure if I understand the question fully. If anyone could at least tell me whether I'm correctly interpreting the question...
 

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