1. The problem statement, all variables and given/known data A new experiment is created with the screen at a distance of 2.2 m from the slits (with spacing 0.12 mm). What is the distance between the second order bright fringe of light with l = 683 nm and the third order bright fringe of light with l = 400 nm? (Give the absolute value of the smallest possible distance between these two fringes: the distance between bright fringes on the same side of the central bright fringe.) 2. Relevant equations sin∅=mλ/d 3. The attempt at a solution For first wavelength, ∅=arcsin(2(683*10^-9)/1.2*10^-4) ∅=.65 Setting up triangle, I get D_683=2.2tan(.65)=.0249 For second wavelength, ∅=arcsin(3(400*10^-9)/1.2*10^-4) ∅=.57 Setting up triangle, I get D_400=2.2tan(.57)=.0219 I thought that D_683-D_400 should give me the distance between the two fringes but my answer of .003m keeps getting rejected. I have done this problem over and over and I cannot for the life of me figure out what I am doing wrong.