The problem involves a driver slowing a car from an initial speed of 33.5 km/hr at a constant deceleration of 0.29 m/s². The objective is to calculate the distance the car travels specifically during the fifth second of coasting.
Some participants have offered guidance on using kinematic equations and clarified the time intervals involved. There is acknowledgment of confusion regarding the definition of the fifth second, but no consensus has been reached on the correct approach yet.
Participants are working under the constraints of a homework assignment, which may limit the information they can use or the methods they can apply. The original poster's calculations have been questioned, indicating a need for further exploration of the problem's requirements.
black_hole said:initial velocity = 9.306m/s
acceleration = -.29m/s/s
time = 5s
displacement = x
x = initial velocity *time + 1/2at*t
x = 42.905m
JDHalfrack said:Use your kinematics.
You know the following:
vi = 33.5 km/hr
a = -0.29 m/s2
"During the fifth second" means you start at 5 seconds and end an instant before the 6th second. So, you need to find the [tex]\Delta[/tex]x at t = 5 and t = 6.
Now, what you do with that knowledge is up to you. I probably told you too much as it is.
Good luck!
Would that not be during the 6th second? From 0s to 1s would be the first second, 1s to 2s is the second second etc., So the 5th second should be from 4s to 5s?