Divergence of dyadic product of a dyadic and vector

Click For Summary
SUMMARY

The discussion centers on calculating the divergence of a triadic expression represented as ∇.((xi × xj × xk)/r^3), where the dyadic product is denoted by × and r is the magnitude of the vector r. The components xi, xj, and xk correspond to the components of the vector r, and the expression can be reformulated as ∇.((xixjxk ei×ej×ek)/r^3). The user seeks the exact expression for the divergence of the dyadic product of a dyadic and a vector, confirming familiarity with the divergence of a dyadic and suggesting the iterative approach of treating the triadic as a product of dyadic and vector.

PREREQUISITES
  • Understanding of vector calculus, specifically divergence operations.
  • Familiarity with dyadic products and triadic tensors.
  • Knowledge of unit vectors and their representation in vector notation.
  • Proficiency in mathematical notation involving tensor products.
NEXT STEPS
  • Research the properties of dyadic products in vector calculus.
  • Study the divergence theorem as it applies to tensor fields.
  • Explore the iterative approach to tensor operations in advanced calculus.
  • Learn about triadic tensors and their applications in physics and engineering.
USEFUL FOR

This discussion is beneficial for mathematicians, physicists, and engineers who are working with tensor calculus, particularly those interested in the divergence of dyadic and triadic products in vector fields.

praban
Messages
13
Reaction score
0
I would like to take divergence of the following expression

∇.((xi × xj × xk)/r^3), which is a triadic.

here × denote a dyadic product and r=mod(r vector) and xi, xj and xk are the components of r vector. So, the above eq. can also be written as

∇.((xixjxk ei×ej×ek)/r^3), where ei, ej and ek are unit vectors in i, j and kth directions.

I know how to take divergence of a dyadic. I guess that we can write the triadic as a product of dyadic and vector and then proceed. I am looking for the exact expression of the divergence of dyadic product of a dyadic and a vector.

I would appreciate any help.

Praban
 
Physics news on Phys.org
praban said:
I know how to take divergence of a dyadic.
Then you can simply iterate the procedure: ##a\otimes b \otimes c= (a\otimes b ) \otimes c##.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 18 ·
Replies
18
Views
18K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K