Do antireflective coats increase the angle of total internal reflectio

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SUMMARY

This discussion focuses on the impact of antireflective (AR) coatings, specifically a 1/4 wavelength layer of magnesium fluoride (MgF2) with an index of refraction of 1.38, on the angle of total internal reflection in prisms with a higher index of refraction (1.7). Participants explore how adding nanoparticles with an index of 1.18 on top of the MgF2 layer may affect light transmission and reflection angles. The consensus indicates that while AR coatings can reduce reflections, they do not significantly alter the maximum angle of total internal reflection, which is fundamentally determined by the refractive indices of the materials involved. Additionally, using specially shaped materials or modifying surface geometries can enhance transmission and reduce aberrations.

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  • Understanding of total internal reflection and critical angles
  • Knowledge of refractive indices and their impact on light behavior
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Optical engineers, lens designers, and anyone involved in the development of optical systems seeking to optimize light transmission and minimize reflections in high-performance applications.

Stargazer19385
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And I mean the angle with the normal vector.

Suppose you shine a laser through a prism at a large angle of incidence, and the prism has index of refraction 1.7. You get the angle of incidence high enough, and you get total internal reflection. Then you put a 1/4 wavelength layer of MgF, index 1.38 on the face of the prism where the total internal reflection is occurring. Would the prism the let some light through, and then have the same total internal reflection angle that a pure MgF prism would have, allowing a higher angle with the normal?

I'm designing an eyepiece and trying to figure out just how much bending I can get away with. What if some nanoparticles are added on top of the MgF, giving a second layer of index 1.18? Would that allow significantly higher angles? Would the nano particles likely be uneven and cause scattering? Nikon claims to have that technology.
 
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I'm no expert, but doesn't total internal reflection depend on the difference between the to mediums' refractive indices? I would expect that adding a layer of something with a refractive index in between that of the two mediums would give you less of an angle. But I could be mistaken.
 
That intermediate index is what I was basing my hope on. I just did not know if there was a certain thickness required in wavelengths for the light to register the intermediate layer. The layer is thick enough to reduce reflections from both sides of a piece of glass at zero incident angle, but I don't know how much it helps at non-normal angles. Wide angle eyepieces usually use 3 lenses to bend the light sufficiently, possibly for the purpose of avoiding high incidence angles, or possibly just to avoid manufacturing a highly curved lens. I wanted to do it in two lenses to reduce the total number of reflections.
 
Oh, I see what you're wanting to do.
Honestly, I'm not sure. Just going off the basics of what I know, it seems like it would work, however it could be that I have no idea what I'm talking about and that it's much more complicated than I think.

I can say that reducing the number of lenses will require that the remaining two have increased curvature, which means that aberrations will be higher and harder to correct.
 
The product of the refractive index and the sine of the angle with the normal is the same in every medium:

Nisinαi=No sin(αo), where No and αo refer to air.

Let the angle in the prism be greater than the critical angle N2sinα2>1 (sinα2>0.588, α2>36°.
With a layer on the prism, the sine of the angle of the light inside the layer is sinα1= N2sin(α2)/N1, sinα1=1.7/1.38sin(α2) for the MgF2 film. If 0.588<sin(α2) <0.81, (36°<α2<54°) the light enters into the layer and reaches the layer-air interface, but will be totally reflected there, as

N1sinα1=N1(N2sin(α2)/N1) = N2sin(α2) >1. You can not avoid totalreflection at the end.

ehild
 
http://refractiveindex.info/?group=PLASTICS&material=PMMA

I looked at the reflection graphs for different materials, including MgF, and found that as the index of refraction goes down, the angle with 5% reflection goes up a bit, but not as much as I would expect. Lowering the index of refraction just seems to shave 2% or so off across most angles. If 6% is acceptable, I might be able to get the 90 degree apparent FOV I want. The nice thing is the reflection will be angled up at the walls instead of the other lenses. I would just need to make sure that light is absorbed. Maybe put some MgF nano particles on the black walls with baffles too.
 
ehild said:
You can not avoid totalreflection at the end.

You cannot avoid it if you insist on parallel surfaces. One solution to modify the effective critical angle lies in putting some thicker specially shaped second material instead of a thin ar-coating layer on the prism.

I have seen people putting hemispheres directly on a sample inside a cryostat to modify the effective limiting angle of total internal reflection. You cannot change the limiting angle between the beam and the normal at the hemisphere-air interface, but by using a hemisphere you can make sure that there is no angle between the beam and the surface normal.
 
By parallel surface, I think you mean plano surface, such as the plano back side of an convex plano lens where the bent rays hit it at a non zero angle on the way out, which is more angle sensitive than the way in. Carving the back side to be spherical concave, with a radius of curvature such that all the out going rays are normal to the surface, not only increases transmission and reduces reflections, but also reduces chromatic aberration.

I still have to get by the high angle of the low f# lens's convex surface. The consensus seems to be that a thin AR coating will not change the maximum allowed angle, or not by much.
 

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