Do i need to find the x and y components?

AI Thread Summary
When a ball is shot at an angle of 55 degrees, its time in the air will be shorter compared to a vertical shot. The initial vertical velocity can be calculated by reducing the vertical component based on the launch angle. An algebraic expression for the initial vertical velocity is sufficient for the problem, rather than a numerical value. The given time of 1.34 seconds can be incorporated into the calculations to determine the impact of the angle on flight duration. Understanding these components is crucial for solving the problem effectively.
crism7
Messages
8
Reaction score
1
Homework Statement
j
Relevant Equations
t = 2vi sin theta / g (i'm not sure)
Do i need to find the x and y components??
j
 
Last edited:
Physics news on Phys.org
Welcome to PF. :smile:

You are given how long the ball stays in the air when shot vertically. What is different when it is shot up at an angle of 55 degrees? It will stay in the air a shorter time, but by how much? What is the initial vertical velocity reduced to when the launch angle is 55 degrees?
 
To @crism7 : Note that @berkeman is not expecting you to find a number for the initial vertical velocity. An algebraic expression will be sufficient. Then see how you can work the given 1.34 s into it.
 
  • Like
  • Informative
Likes berkeman and crism7
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top