Two teams, A and B, play a series of games. If team A has probability .4 of
winning each game, is it to its advantage to play the best three out of five games
or the best four out of seven? Assume the outcomes of successive games are
The Attempt at a Solution
This problem is basically a plug and chug problem. However, I do have some difficulties interpreting this problem.
When the problem states "the best three out of five games" and "the best four out of seven games", does it mean that when Team A wins three times or four times (given the respective parameters), does the game end???
Example 1: Team A wins three times -> game is over.
Example 2: Team A wins three times -> game continues until 5 games are played.
Since a person can interpret this many ways, I decided to just write out the solution for each example.
Solution 1: Take the summation of the negative binomial distribution of 3 successes, p = 0.4, and the number of trials from i = 3 to i = 5.
Solution 2: Take the summation of the binomial distribution from i number of successes from i = 3 to i = 5, p = 0.4, and the number of trials is 5.
Assuming that if both the cases were true, is my solution or "method" for each one correct? I know that 3 out of 5 game is the correct answer; nevertheless, I am just curious at the process to reach it because many people I met have different interpretations and methods to answer this problem.