B Do Wedge Constraint Relations Affect Velocities Parallel to the Contact Surface?

AI Thread Summary
The discussion centers on the dynamics of a rigid rod and a wedge, focusing on the velocities involved when the rod is in contact with the wedge. It is established that the velocities perpendicular to the contact surface must be equal due to wedge constraint relations, specifically expressed as vcosθ = usinθ. However, the participants debate whether there are any constraints on their velocities parallel to the contact surface, with the consensus being that there are none, as maintaining contact is governed by a displacement constraint rather than a velocity constraint. Concerns are raised about the rod losing contact with the wedge if its parallel velocity component is non-zero, but this is clarified as a misunderstanding of the constraints involved. Ultimately, the discussion concludes that the finite size of the wedge creates a displacement constraint rather than imposing additional velocity constraints.
newbie12321
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Why is there no constraint on the component of velocities parallel to the contact surface?
There’s a rigid rod pushing on a wedge. Velocity of the rod is v, which is vertically downwards, and the wedge is sliding to the right as a result with a velocity u. There is zero friction on the surface of the wedge and the surface of the rod in contact with the wedge.
According to wedge constraint relations, if the rod stays in contact with the wedge, then its relative velocity with respect to the wedge perpendicular to the contact surface must be zero. It means velocity of the rod and the wedge perpendicular to the contact surface must be equal, i.e

vcosθ = usinθ

My question is, what about their velocities parallel to the contact surface? Is there no constraint on their velocities parallel to the contact surface if both the rod and the wedge have to stay in contact?

If their relative velocity parallel to the contact surface is non-zero, the rod will keep sliding down the wedge, won’t it lose contact with the wedge after it reaches the bottom? Likewise, if the rod were sliding up the wedge, won’t it lose contact when it finally comes off the top of the wedge? Hope I am able to explain what I want to understand. Is it because the wedge doesn’t extend infinitely? This is something I am not able to understand. Please help me with it. I have attached a picture. Thanks

*Edit : Angle of inclination of the wedge is θ, not α
 

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newbie12321 said:
Is it because the wedge doesn’t extend infinitely?
That's not a velocity constraint, but a displacement constraint.
 
A.T. said:
That's not a velocity constraint, but a displacement constraint.
My question is, is there no constraints on their velocities parallel to the contact surface?
 
newbie12321 said:
My question is, is there no constraints on their velocities parallel to the contact surface?
Why would there be any?
 
If you require contact with the wedge, there is only ONE constraint .

You can express it in many ways, all equivalent (e.g. the one you mention).
 
A.T. said:
Why would there be any?
Like I have said in my post, if the component of relative velocity between the rod and the wedge parallel to the contact surface is non-zero, the rod will slide off the edge and will lose contact with the wedge as a result. That's what got me wondering as to why there is no constraint on their velocities parallel to the contact surface?
Hope I am able to explain it well
 
BvU said:
If you require contact with the wedge, there is only ONE constraint .

You can express it in many ways, all equivalent (e.g. the one you mention).
BvU said:
If you require contact with the wedge, there is only ONE constraint .

You can express it in many ways, all equivalent (e.g. the one you mention).
If the component of relative velocity between the rod and the wedge parallel to the contact surface is non-zero, would the rod not slide off the edge of the wedge, and lose contact with it as a result?
 
newbie12321 said:
Like I have said in my post, if the component of relative velocity between the rod and the wedge parallel to the contact surface is non-zero, the rod will slide off the edge and will lose contact with the wedge as a result. T
Like I have said in my post, the size of the ramp imposes a displacement constraint, not a velocity constraint.
 
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A.T. said:
Like I have said in my post, the size of the ramp imposes a displacement constraint, not a velocity constraint.
Got it. Thanks a lot.
 
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