Does a photon have "resting" mass?

In summary: The invariant mass of a free photon is 0, but if you put it in a medium, you can define the retarded photon propagator and a spectral function from it (in thermal equilibrium it's either the analytic continuation of the in-medium Matsubara propagator to real time or equivalently the corresponding matrix element of the Schwinger-Keldysh contour propagator). If this spectral function is sharply peaked enough, you can use a quasi-particle description and define an invariant mass of the photon through the corresponding dispersion relation, otherwise this doesn't make sense und you have to use the broad spectral distribution to describe the corresponding plasmon excitations.
  • #1
psuedoben
36
2
if so, what is that and how is resting mass different than just mass?
 
Physics news on Phys.org
  • #2
The photon mass is zero and it is not very correct to talk about a photon rest mass as they cannot be at rest. For massive particles, rest mass is what physicists normally refer to when they say "mass". The term "relativistic mass" is not used much and you will have a hard time finding a physicist who refers to it as just "mass".
 
  • #3
Orodruin said:
The photon mass is zero and it is not very correct to talk about a photon rest mass as they cannot be at rest. For massive particles, rest mass is what physicists normally refer to when they say "mass". The term "relativistic mass" is not used much and you will have a hard time finding a physicist who refers to it as just "mass".
Ok, thank you. I was just confused I had because I had always been told they had no mass at all (because they don't interact with the Higgs fields right?) so it didn't make sense to me as to why they would have resting mass
 
  • #4
In almost all the cases, the photons are massless.. Only under certain conditions, you can give them an effective mass.
They are massless (rest mass =0 ) because they don't interact with Higgs, but ... we knew before Higgs that they should be massless, for many reasons- one of which is that they travel at [itex]c[/itex], or that Coulomb's law make the force have infinite range, etc...
 
Last edited:
  • Like
Likes psuedoben
  • #5
Please, in English, we say "rest mass", not "resting mass."
 
  • Like
Likes bcrowell and psuedoben
  • #6
Since photons have zero rest mass, the gravitational lensing effect must prove the existence of the photon's effective mass, when traveling at c.
 
  • #7
It does not, no matter what "effective mass" is supposed to mean. The photons simply follow curved spacetime, as all other objects.
 
  • Like
Likes bcrowell
  • #8
Ah. Thanks.
 
  • #9
jtbell said:
Please, in English, we say "rest mass", not "resting mass."
Heh,... and I really wish we would always say "invariant mass" instead of "rest mass". :oldwink::oldbiggrin:
 
  • Like
Likes vanhees71
  • #10
Just say "mass" as nearly all physicists do.

If the system is not a single particle (or decay products of a single particle), "invariant mass" is clearer, but not necessary.
 
  • Like
Likes bcrowell
  • #11
Well, in the forum I talk about "invariant mass". In daily life, I just say mass, because nobody in my environment would misunderstand it to be some strange old-fashioned quantity known as the "relativistic mass" ;-)).
 
  • #12
Photon has no rest mass. In solid material where you have spontaneous breaking of phase symmetry (Anderson-Higgs phenomenon, condensed matter version of Higgs mechanism), it would acquire a mass. In which case it becomes dispersive and group velocity would be different from c.

I am guessing the 'mass' you are referring to is possibly the relativistic mass. It is related to energy, which is not an invariant quantity. General relativistic gravitation is related to the energy-momentum density; in that sense, for a photon gas, there would be frame involving energy density and pressure and this energy density might have an effective gravitating mass density (you still have to take the gravitational effect of pressure relativistically though).
 
  • #13
As stated before in relativistic theory for decades one uses the word mass only for "invariant mass". Only very rarely you find proponents of the old-fashioned idea of "relativistic mass", which were invented in the very early days of relativity (they even had two kindes of "relativistic mass", a transverse and longitudinal one). In my opinion, this notions were obsolete with Minkowski's famous talk on the mathematical structure of (special) relativistic spacetime.

The invariant mass of a free photon is 0. In a medium you can define the retarded photon propagator and a spectral function from it (in thermal equilibrium it's either the analytic continuation of the in-medium Matsubara propagator to real time or equivalently the corresponding matrix element of the Schwinger-Keldysh contour propagator). If this spectral function is sharply peaked enough, you can use a quasi-particle description and define an invariant mass of the photon through the corresponding dispersion relation, otherwise this doesn't make sense und you have to use the broad spectral distribution to describe the corresponding plasmon excitations.
 

1. What is a photon and does it have mass?

A photon is a type of elementary particle that carries the electromagnetic force. According to the theory of relativity, it has no rest mass but does have energy and momentum.

2. Is a photon considered a matter or antimatter particle?

A photon is not considered a matter or antimatter particle because it has no rest mass and therefore does not interact with the Higgs field, which is responsible for giving particles their mass.

3. Can a photon have a measurable mass?

No, a photon cannot have a measurable mass because it travels at the speed of light and therefore has no rest mass. Its energy and momentum are attributed to its frequency and wavelength.

4. How does the concept of mass-energy equivalence apply to photons?

Einstein's famous equation, E=mc², states that mass and energy are interchangeable. For particles with no rest mass, such as photons, their energy is equal to their mass multiplied by the speed of light squared.

5. Can a photon be affected by gravity?

Yes, although a photon has no rest mass, it does have energy and momentum, which means it can be affected by gravity. This is seen in phenomena such as gravitational lensing, where the path of light is bent by the gravitational pull of a massive object.

Similar threads

  • High Energy, Nuclear, Particle Physics
Replies
4
Views
1K
  • High Energy, Nuclear, Particle Physics
Replies
3
Views
958
  • High Energy, Nuclear, Particle Physics
Replies
12
Views
2K
  • High Energy, Nuclear, Particle Physics
Replies
13
Views
2K
  • High Energy, Nuclear, Particle Physics
Replies
6
Views
1K
  • High Energy, Nuclear, Particle Physics
2
Replies
46
Views
4K
  • High Energy, Nuclear, Particle Physics
Replies
1
Views
1K
  • High Energy, Nuclear, Particle Physics
Replies
1
Views
932
  • High Energy, Nuclear, Particle Physics
Replies
5
Views
2K
  • High Energy, Nuclear, Particle Physics
Replies
4
Views
2K
Back
Top