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johne1618
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The Hawking-Unruh temperature is given by the expression:
\large T = \frac{\hbar g}{2 \pi c k}
where g is the gravitational acceleration at the surface of a black hole.
Does this expression imply that any gravitating body will emit Hawking radiation?
For example if we take the acceleration due to gravity at the Earth's surface to be g = 10 \ m/s^2 does that mean that the Earth emits Hawking radiation at a temperature T = 10^{-20} K?
John
\large T = \frac{\hbar g}{2 \pi c k}
where g is the gravitational acceleration at the surface of a black hole.
Does this expression imply that any gravitating body will emit Hawking radiation?
For example if we take the acceleration due to gravity at the Earth's surface to be g = 10 \ m/s^2 does that mean that the Earth emits Hawking radiation at a temperature T = 10^{-20} K?
John
