Does buoyancy affect the extension of a real spring?

  • #1

Main Question or Discussion Point

In Hooke's law, F=-kx. Assume that a mass is hung from the end of an ideal massless spring, the spring stretches a distance of x.
However, in real life the spring has mass and it is submerged in a "fluid" of air. Compared to an ideal spring, would the real spring have a slightly different extension due to buoyancy?
 

Answers and Replies

  • #2
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In Hooke's law, F=-kx. Assume that a mass is hung from the end of an ideal massless spring, the spring stretches a distance of x.
However, in real life the spring has mass and it is submerged in a "fluid" of air. Compared to an ideal spring, would the real spring have a slightly different extension due to buoyancy?
Ideally, it should have an effect. But the buoyancy due to air is so negligible, that it doesn't make a big difference.
 

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