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Does buoyancy affect the extension of a real spring?

  1. Feb 1, 2015 #1
    In Hooke's law, F=-kx. Assume that a mass is hung from the end of an ideal massless spring, the spring stretches a distance of x.
    However, in real life the spring has mass and it is submerged in a "fluid" of air. Compared to an ideal spring, would the real spring have a slightly different extension due to buoyancy?
  2. jcsd
  3. Feb 1, 2015 #2
    Ideally, it should have an effect. But the buoyancy due to air is so negligible, that it doesn't make a big difference.
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