Does Mixing Fluids A and B Create a Predictable Thermal Capacity?

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SUMMARY

The discussion confirms that the thermal capacity of a mixture of fluids A and B can be calculated using the formula C_new = C_a * X + C_b * (1-X) if the fluids form an "ideal solution." An ideal solution is characterized by similar molecular attractions between the components, meaning the interactions between A and A, B and B, and A and B are nearly identical. If these conditions are not met, the relationship may vary and cannot be generalized.

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  • Understanding of thermal capacity concepts
  • Knowledge of ideal solutions in chemistry
  • Familiarity with fluid mixtures and their properties
  • Basic principles of molecular interactions
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Chemists, chemical engineers, and students studying thermodynamics and fluid dynamics will benefit from this discussion, particularly those interested in the thermal properties of fluid mixtures.

pomekrank
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Hi,
Say we have fluid A with thermal capacity C_a and fluid B with C_b. If we create a solution with X% of fluid A and (1-X)% of fluid B, is it true that the new thermal capacity of the mixture will be
C_new ?= C_a*X + C_b * (1-X)
Or it is a case-by-case relationship that depends on the nature of the fluids ?

Thank you
 
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Case by case.
 
pomekrank said:
Hi,
Say we have fluid A with thermal capacity C_a and fluid B with C_b. If we create a solution with X% of fluid A and (1-X)% of fluid B, is it true that the new thermal capacity of the mixture will be
C_new ?= C_a*X + C_b * (1-X)
Or it is a case-by-case relationship that depends on the nature of the fluids ?

Thank you
If A and B form a so-called "ideal solution," then your mixing rule is correct. For a solution to be ideal, the molecular attractions between A and A, B and B, and A and B must be nearly the same.
 

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