Does the half-life of a radioactive element stay the same?

AI Thread Summary
The half-life of a radioactive element remains constant regardless of changes in temperature or pressure. Each radionuclide has a unique half-life that cannot be altered by any chemical or physical processes. The discussion also touches on gaseous radioactive waste products, specifically mentioning radon-222, radium-226, cesium-137, and cobalt-60. It is emphasized that no method exists to accelerate the decay process of radionuclides. Understanding these principles is crucial for managing radioactive materials safely.
UrbanXrisis
Messages
1,192
Reaction score
1
As the temperature increases and pressure remaining constant. Does the half-life of a radioactive element stay the same?

Also, Which gaseous radioactive waste product that is released into the atmosphere after it has decayed to a safe radiation level?
radon-222, radium-226, cesium-137, cobalt-60 ?
 
Last edited:
Physics news on Phys.org
search google-- btw I sent the card you wanted

lol i read half-life and thought u were talking about the video game
 
Can I make the process hurry along?
Unfortunately, no. Each radionuclide has its own characteristic half-life. No operation or process of any kind (i.e., chemical or physical) has ever been shown to change the rate at which a radionuclide decays.

from a website... I assume temp is includded
 
Tom McCurdy said:
search google-- btw I sent the card you wanted

lol i read half-life and thought u were talking about the video game
:smile: :-p
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top