Does the Limit of 3xy/((x^2)+(4y^2)) as (x, y) Approaches (0,0) Exist?

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Evaluate the limit or prove that it does not exist..

f(x,y) -> (0,0)
3xy/((x^2)+(4y^2))

The attempt at a solution:

Set x to 0 and you get 0
set y to 0 and you get 0
set y=x and you get 3x^2/5x^2 = 3/5
This means that limit does not exist.

Is this correct?
If this is correct, how do you know that you have to set y=x? Is there a generic approach to these kinds of problems?
Thank you for taking the time to read this and for your help.
 
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welcome to pf!

hi manjum423! welcome to pf! :smile:

(try using the X2 button just above the Reply box :wink:)
manjum423 said:
Set x to 0 and you get 0
set y to 0 and you get 0
set y=x and you get 3x^2/5x^2 = 3/5
This means that limit does not exist.

Is this correct?

completely :smile:
If this is correct, how do you know that you have to set y=x? Is there a generic approach to these kinds of problems?

you try y = kx first (for constant k),

if that doesn't work, try y = kxn

if that doesn't work, assume the limit exists, and try to prove it!

alternatively, use polar-ish coordinates, eg x = 2rcosθ, y = rsinθ, giving … ? :wink:
 
manjum423 said:
Evaluate the limit or prove that it does not exist..

f(x,y) -> (0,0)
3xy/((x^2)+(4y^2))

The attempt at a solution:

Set x to 0 and you get 0
set y to 0 and you get 0
set y=x and you get 3x^2/5x^2 = 3/5
This means that limit does not exist.

Is this correct?
If this is correct, how do you know that you have to set y=x? Is there a generic approach to these kinds of problems?
Thank you for taking the time to read this and for your help.
Hello manjum423 . Welcome to PF !

We do like you to use the supplied homework template.

Homework Statement



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The Attempt at a Solution


You seem to have some difficulty writing you problem. It appears that you problem is something like:
Evaluate the limit or prove that it does not exist..

Lim(x,y)→(0,0) 3xy/((x2)+(4y2))

Which can be displayed more nicely using LaTeX.

##\displaystyle \lim_{(x,y)\to(0,0)} \frac{3xy}{(x^2)+(4y^2)}##

Your solution is correct.

For your problem, the method you used works fine.

You could make it a bit more general by approaching the origin along the arbitrary line , y = mx .

That method doesn't always work either.

One pretty good scheme is to change to polar coordinates. Then only one variable, r, goes to zero. The other, θ, remains arbitrary.
 
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