Does the Series Converge or Diverge?

  • Thread starter Thread starter I'm Awesome
  • Start date Start date
  • Tags Tags
    Series
I'm Awesome
Messages
14
Reaction score
0

Homework Statement


Determine whether the infinite series converges or divergens. If it converges find its sum.
\sum^{∞}_{k=1} \frac{k-3}{k}


Homework Equations





The Attempt at a Solution



I found the limit and realized that the limit is 1. So I said that the series converges by the test for divergence. And since it diverges I don't have to worry about finding a sum.


However, I'm not sure if I'm using the test for divergence right.
 
Physics news on Phys.org
I'm Awesome said:


I found the limit and realized that the limit is 1. So I said that the series converges by the test for divergence. And since it diverges I don't have to worry about finding a sum.



You are contradicting yourself. Do you think it converges or diverges ?

Hint: This series doesn't converge try and use a comparison test too see why.
 
sid9221 said:
You are contradicting yourself. Do you think it converges or diverges ?

Hint: This series doesn't converge try and use a comparison test too see why.

Sorry, I ment to say that the series diverges by the test for divergence because the limit is not equal to 0.
 
Yes, by the non null test is this is divergent as the limit is not equal to zero.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Back
Top