Does the Series \(\sum_{n=1}^{\infty} \frac{5+n \cos n}{n^2+2^n}\) Converge?

  • Context: MHB 
  • Thread starter Thread starter maxkor
  • Start date Start date
  • Tags Tags
    Series
Click For Summary
SUMMARY

The series \(\sum_{n=1}^{\infty} \frac{5+n \cos n}{n^2+2^n}\) converges. The ratio test is applicable here, where the comparison series \(\sum_{n=1}^{\infty} \frac{5+n}{2^n}\) is shown to converge. By establishing that \(\left|\frac{5 + n\cos n}{n^2 + 2^n}\right| \le \frac{5 + n}{2^n}\), the convergence of the original series can be concluded through the comparison test.

PREREQUISITES
  • Understanding of series convergence tests, particularly the ratio test.
  • Familiarity with comparison tests in series analysis.
  • Basic knowledge of trigonometric functions, specifically cosine.
  • Experience with limits and asymptotic behavior of functions.
NEXT STEPS
  • Study the ratio test in detail, focusing on its application in series convergence.
  • Learn about comparison tests and their use in determining series convergence.
  • Explore the behavior of trigonometric functions within series, particularly in oscillatory contexts.
  • Investigate the convergence of series involving exponential functions, such as \(\sum_{n=1}^{\infty} \frac{1}{2^n}\).
USEFUL FOR

Mathematicians, students studying calculus or real analysis, and anyone interested in series convergence and advanced mathematical concepts.

maxkor
Messages
79
Reaction score
0
\sum_{n=1}^{ \infty } \frac{5+n cosn}{n^2+2^n} is convergent?
 
Physics news on Phys.org
maxkor said:
\sum_{n=1}^{ \infty } \frac{5+n \cos n}{n^2+2^n} is convergent?
Have you tried using the ratio test?
 
If $\left \{ a_n \right \}, \left \{ b_n \right \} > 0$, and the limit $ \lim_{n \to \infty} \frac{a_n}{b_n}$ exists, is finite and is not zero, then $\sum_{n=1}^\infty a_n$ converges if and only if $\sum_{n=1}^\infty b_n converges.$
But $\left \{ b_n \right \} =??$
 
maxkor said:
\sum_{n=1}^{ \infty } \frac{5+n cosn}{n^2+2^n} is convergent?

Hi maxkor,

While I agree with the suggestion posted by Opalg, I think it should be used indirectly. More precisely, since

$$\left|\frac{5 + n\cos n}{n^2 + 2^n}\right| \le \frac{5 + n}{n^2 + 2^n} < \frac{5 + n}{2^n},$$

use the ratio test to show that $\sum\limits_{n = 1}^\infty \frac{5 + n}{2^n}$ converges, then conclude by comparison that $\sum\limits_{n = 1}^\infty \frac{5 + n\cos n}{2^n}$ converges.
 
Last edited:

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
3
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K