- #1

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I know the expression for the angle the new water level makes with the old one(horizontal).

But how do I know their point of intersection?

Note : Of course the container is not full.

- Thread starter s0ft
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- #1

- 83

- 0

I know the expression for the angle the new water level makes with the old one(horizontal).

But how do I know their point of intersection?

Note : Of course the container is not full.

- #2

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Could you be a little more vague? I can almost understand what you are asking but if you could just obfuscate the issue a bit more, I could be completely baffled

I know the expression for the angle the new water level makes with the old one(horizontal).

But how do I know their point of intersection?

Note : Of course the container is not full.

- #3

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An open cubical container with 2.5 m x 1 m base and 2 m height, half full with water is accelerated at 4ms

- #4

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Indeterminate since you have not specified whether the long axis or short axis is pointing uphill. Don't you think that might matter?

An open cubical container with 2.5 m x 1 m base and 2 m height, half full with water is accelerated at 4ms^{-2}up on a 15 degree incline along its length. Will the water spill?

Oh, and by the way, you won't get any help here unless you show some work of your own. I'm just trying to get you to post a question that HAS an answer.

EDIT: DOH !! You DID say "along it's length". I can't read.

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