Does this has anything to do with relativity?

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The discussion revolves around calculating the time it takes for the Starship Enterprise to reach the moon at a speed of 0.7c, with the distance to the moon being 384,000 km. The initial calculation provided yields approximately 1.83 seconds using the formula time equals distance divided by speed. However, there is concern about whether relativistic effects, such as time dilation, should be considered in this scenario. It is noted that from the Earth's frame of reference, the calculation appears straightforward, while the crew on the ship would experience time differently. The conclusion emphasizes the distinction between the Earth’s reference frame and the crew's perspective in terms of time measurement.
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Homework Statement


The Starship Enterprise, apparently escaping from the clutches of Cthulhu (the image was not altered, this is how it was given!) is flying to the moon at a velocity of 0.7c.
How long will it take (in seconds) for it to get to the moon, as observed from the Earth's frame of reference.
D from Earth to the Moon is 384,000 Km.
At t=0 the ship is over the earth

http://img229.imageshack.us/img229/4001/spaceshiptothemoon.png

Homework Equations



Time=distance/speed...

The Attempt at a Solution



Am I wrong to assume this has nothing to do with relativistic time dilation or shortening of distances and what-not?
This seems to be a straightforward calculation.
So is this right:
384,000 Km = 3.84*10^8 m
c = 3*10^8 m/s
\frac{3.84*10^8}{0.7*3*10^8} = 1.828571428 seconds.

I got this in a relativity assignment so I'm suspicious of this solution.
If I missed something please let me know.*can't edit the title, obviously should be "have"...
 
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In the Earth's reference frame it's just the distance and time.
From the point of view of the crew time would be different.
 
Thank You!
 
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