How Does Wind Affect the Doppler Effect in a Two-Train Scenario?

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SUMMARY

The discussion focuses on calculating the frequency heard by a train when a whistle is blown, considering the Doppler Effect and the influence of wind. The scenario involves two trains moving towards each other at 30.0 m/s, with one train emitting a whistle at 480 Hz and wind blowing at 30.0 m/s towards the whistle. The correct formula to apply is F' = F((V + V_d) / (V - V_d)), where the velocities must be considered relative to the medium, leading to a frequency adjustment based on the wind's direction.

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  • Understanding of the Doppler Effect
  • Familiarity with sound wave propagation
  • Knowledge of relative velocity concepts
  • Basic algebra for manipulating equations
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  • Learn about sound wave propagation in moving media
  • Explore the impact of wind on sound frequency
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Homework Statement


Two trains are traveling toward each other at 30.0 m/s relative to the ground. One train is blowing a whistle at 480 Hz. (a)What frequency is heard on the other train if the wind is blowing at 30.0 m/s toward the whistle and away from the listener? (assume the speed of sound is 343m/s)

Homework Equations


F'=F((V+V_d)/(V-V_d))



The Attempt at a Solution


Well the top velocity has a + and the bottom has a minus because they're going towards each other and the wind is going away from the listener and towards the source.
So I just assumed F'=480((343+30+30)/(343-30+30)) since this is the vector sum? This is wrong however and it's actually the opposite, so I need help understanding why conceptually
 
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You need to take each speed relative to the medium.
 

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