Dot product and cross product of vectors

AI Thread Summary
The discussion focuses on evaluating the dot and cross products of the vectors v, u, and w. The user attempts to determine which expressions are valid based on the mathematical operations involved. They correctly identify that the first and last expressions can be evaluated, while the second and third contain inconsistencies due to mixing scalars and vectors. Another participant suggests using a math package like SymPy for verification and points out a minor error in counting scalars in the last expression. The conversation emphasizes understanding vector operations and ensuring proper evaluation of mathematical expressions.
warfreak131
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Homework Statement



This isn't so much a problem of calculation, so much as it is I need to know if i did it right, you'll see what I mean.

vectors v=(2,0,2), u=(-1,1,0), w=(0,-1,1)
Computer the quantities that make sense (a period denotes the dot product, x denotes cross product):

(v.u)w

(v x u) x w + 1

(v x u) + (v.u)

(v x u) . w + (v x w) . u + 1


The Attempt at a Solution




I said that the first one is the form of scalar * vector which equals a vector

the second is the product two cross vectors, which is a vector, plus a scalar, which does not make sense.

The third has the form of a vector plus a scalar, which doesn't make sense

and the fourth:

(v x u) . w
is a vector cross vector, which is a vector, dotted with another which is a scalar

(v x w) . u + 1
is a vector cross vector, which is a vector, dotted with a vector, which is a scalar, plus 1, which is a scalar, so youre adding three scalars, which makes sense
 
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I did not see any problem here.
 
cool, thanks
 
wait, do you mean that you don't see what the "question" is, or you don't see a problem with my answer.

the question asks to evaluate the ones that make sense. i evaluated the first and last ones on the test because i thought that those were the ones that make sense. i am asking if those are indeed the ones that can be evaluated.
 
I see the question, but don't see any error on your part.
It is easy to check this kind of things using a math package. My favourite is simpy.
You define v in simpy this way:
v=Matrix([2,0,2])
You express (v x u) . w this way:
(v.cross(u)).dot(w)
Now you got the idea.

Ahh a minor error in your part: in the last one you add two scalars, not three.
 
well (v x u) . w is a scalar

(v x w) . u is a scalar

and 1 is a scalar

but thanks tho
 
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