- #1

pb23me

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## Homework Statement

Use a double integral to find the area of the region bounded by the curve r= 1+sin(theta)?

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- Thread starter pb23me
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- #1

pb23me

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Use a double integral to find the area of the region bounded by the curve r= 1+sin(theta)?

- #2

SammyS

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Have you done a polar plot?## Homework Statement

Use a double integral to find the area of the region bounded by the curve r= 1+sin(theta)?

## Homework Equations

## The Attempt at a Solution

I can't figure out what theta is integrated from. I've tried from -(pi)/2 -> +(pi)/2 and that doesn't work. I've also tried from 0-> 2(pi) and that doesn't work. I have no clue what I'm supposed to integrate theta to. I would really appreciate some help with this.

0 → 2π should give the right answer.

What does your integral look like ?

- #3

- #4

SammyS

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Your integral looks good:i put a picture up

[itex]\displaystyle \int_0^{2\pi}\int_0^{1+\sin(\theta)}r\,dr\,d\theta[/itex]

What do you get for tour final answer?

- #5

pb23me

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I get (3(pi) + 2)/2

- #6

SammyS

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Where does the " + 2 " come from ... as inI get (3(pi) + 2)/2

(3(π) + 2)/2

?What do you get upon integration w.r.t. r ?

- #7

pb23me

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