Double Integral Help: |cos(x+y)| over [0,pi]x[0,pi]

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The discussion focuses on evaluating the double integral of |cos(x+y)| over the rectangle [0, pi] x [0, pi]. A user seeks guidance on how to split the integral to remove the absolute value for easier integration. Suggestions include using polar coordinates, but this approach is deemed inappropriate. Instead, it is recommended to divide the region along the lines x+y=pi/2 and x+y=(3*pi/2) to account for the sign change of the cosine function. This method will facilitate the iterative integration process.
eckiller
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doubleIntegral( |cos(x+y)| dx dy ) over the rectangle [0, pi]x[0,pi]

I tried several ways to split the integral up so that I could remove the absolute value sign and integrate. However, I did not get the correct answer, so I must be splitting it wrong. Can someone show me how to split the region of integration up so I can integrate iteratively?
 
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At a glance, not saying this will work, but try using polar coordinates? ie x^2+Y^2=r^2 and so on.
 
FunkyDwarf said:
At a glance, not saying this will work, but try using polar coordinates? ie x^2+Y^2=r^2 and so on.

Polar coordinates are a bad idea. Cut the square along the lines x+y=pi/2 and x+y=(3*pi/2) - since this is where the cos changes sign.
 
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