Double Integral Help: |cos(x+y)| over [0,pi]x[0,pi]

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SUMMARY

The discussion focuses on evaluating the double integral of |cos(x+y)| over the rectangle [0, pi] x [0, pi]. The user initially attempted to split the integral to eliminate the absolute value but encountered difficulties. A key conclusion is that the correct approach involves dividing the integration region along the lines x+y=pi/2 and x+y=(3*pi/2), where the cosine function changes sign, rather than using polar coordinates, which are deemed inappropriate for this problem.

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doubleIntegral( |cos(x+y)| dx dy ) over the rectangle [0, pi]x[0,pi]

I tried several ways to split the integral up so that I could remove the absolute value sign and integrate. However, I did not get the correct answer, so I must be splitting it wrong. Can someone show me how to split the region of integration up so I can integrate iteratively?
 
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At a glance, not saying this will work, but try using polar coordinates? ie x^2+Y^2=r^2 and so on.
 
FunkyDwarf said:
At a glance, not saying this will work, but try using polar coordinates? ie x^2+Y^2=r^2 and so on.

Polar coordinates are a bad idea. Cut the square along the lines x+y=pi/2 and x+y=(3*pi/2) - since this is where the cos changes sign.
 

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