Double integral with cos(x^n) term

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SUMMARY

The discussion focuses on solving the double integral \(\int _{0}^{\frac{1}{8}}\int _{\sqrt[3]{y}}^{\frac{1}{2}}\cos\left(20{\pi}x^{4}\right)dx\, dy\) without series development. The key insight is that changing the order of integration simplifies the problem, leading to an \(x^3\) term in the integral. Participants emphasized the importance of correctly adjusting the limits of integration, particularly noting the transition from a square root to a cubic root when re-evaluating the limits.

PREREQUISITES
  • Understanding of double integrals
  • Familiarity with trigonometric functions, specifically cosine
  • Knowledge of changing the order of integration
  • Ability to manipulate limits of integration
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  • Study techniques for changing the order of integration in double integrals
  • Explore trigonometric identities relevant to integrals involving cosine
  • Practice solving double integrals with polynomial terms
  • Learn about the implications of limit adjustments in integration
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Students and educators in calculus, particularly those focusing on integral calculus and double integrals, as well as anyone looking to enhance their problem-solving skills in mathematical analysis.

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[SOLVED] Double integral with cos(x^n) term

Homework Statement



Solve the following integral (without using a series development):
\displaystyle<br /> \int _{0}^{\frac{1}{8}}\int _{\sqrt[3]{y}}^{\frac{1}{2}}\cos\left(20{\pi}x}} ^{4}\right)dx dy

Homework Equations



N/A

The Attempt at a Solution



Obviously the cos(x^4) part is what throws me off, I tried switching the order of integration and substituting for various trigonometric identities but it doesn't seem to help much. I'd appreciate any pointers to get me started.
 
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I think changing the order of integration is the way to go. You'll get an x^3 term in the integral with respect to x. Then it's easy.
 
your limits should change too!
I think you did not change the limits
 
Great, thanks, I went back and realized I'd made a stupid mistake and somehow used a square root instead of the cubic root when changing the limits.
 

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