Double Integrals on a Sphere: Solving for f(x,y,z) and g(t)

  • Thread starter Thread starter myfunkymaths
  • Start date Start date
  • Tags Tags
    Integrals
Click For Summary

Homework Help Overview

The problem involves evaluating a surface integral of a function defined in terms of a spherical coordinate system. The function f(x,y,z) is expressed as g(√(x^2 + y^2 + z^2)), and g(t) is given as t-5, with the surface S being a sphere defined by the equation x^2 + y^2 + z^2 = 9.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants are discussing how to approach the integral evaluation, with one questioning the integration of a function over the sphere and the bounds required. Others are considering the implications of the function being constant over the surface.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and questioning the setup and assumptions regarding the function and the integration process.

Contextual Notes

There is uncertainty regarding the specific function to integrate and the bounds for the integration, as well as the implications of the function being constant over the sphere.

myfunkymaths
Messages
5
Reaction score
0

Homework Statement



f(x,y,z) = g(√(x^2 + y^2 + z^2))
g(t) = t-5
evaluate ∯ f(x,y,z)ds

where S is sphere x^2 + y^2 + z^2 = 9


Homework Equations





The Attempt at a Solution



i don't know how to go about it. can someone help me with this, how to approach this from start to end. i will solve it, but i need to know the steps in doing it.
 
Physics news on Phys.org
hi myfunkymaths! :smile:

(have a square-root: √ and try using the X2 icon just above the Reply box :wink:)
myfunkymaths said:
f(x,y,z) = g(√(x^2 + y^2 + z^2))
g(t) = t-5
evaluate ∯ f(x,y,z)ds

where S is sphere x^2 + y^2 + z^2 = 9

uhh? isn't that just integrating r - 5 over the sphere r = 3 ? :confused:
 
tiny-tim said:
hi myfunkymaths! :smile:

(have a square-root: √ and try using the X2 icon just above the Reply box :wink:)


uhh? isn't that just integrating r - 5 over the sphere r = 3 ? :confused:


so what function do i integrate twice? and with what bounds was it
 
but it's constant!
 

Similar threads

Replies
8
Views
2K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
6
Views
2K
Replies
7
Views
2K
Replies
3
Views
2K
Replies
9
Views
3K