Double Slit with Reflections

In summary, the problem involves a radar tower, a weather balloon, and a boat on the ocean. The maximum wavelength that will interfere destructively is given by lambda= 2*[sqrt(h^2 + 2*h*x +x^2 + d^2) - sqrt(h^2 - 2*h*x +x^2 + d^2)], where x is the height of the radar tower, h is the altitude of the balloon, and d is the distance between the boat and the tower. This is due to a pi phase change when the wave is reflected from a medium with a higher refractive index.
  • #1
deathslayer7
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Homework Statement


A radar tower sends out a signal of wavelength lambda. It is x meters tall, and it stands on the edge of the ocean. A weather balloon is released from a boat that is a distance d out to sea. The balloon floats up to an altitude h. In this problem, assume that the boat and balloon are so far away from the radar tower that the small angle approximation holds.

Due to interference with reflections off the water, certain wavelengths will be weak when they reach the balloon. What is the maximum wavelength that will interfere destructively?
Express your answer in terms of x, h, and d.



Homework Equations


maxium deconstructive interference. delta r=m*lambda. Could be wrong though.


The Attempt at a Solution



physics.jpg


I extended (lambda 2) the blue line so it reaches down to the height where the radio tower would be if it was reversed.

I solved for Lamda 1 and 2 getting,

L1^2=h^2 - 2*h*x + x^2 + d^2

L2^2=h^2 + 2*h*x +x^2 + d^2

find delta r by subtracting.

L2 - L1 = sqrt(h^2 + 2*h*x +x^2 + d^2) - sqrt(h^2 - 2*h*x +x^2 + d^2)=lambda/2

lambda= 2*[sqrt(h^2 + 2*h*x +x^2 + d^2) - sqrt(h^2 - 2*h*x +x^2 + d^2)]

but I am doing something wrong. Any help is appreciated.
 
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  • #2
The wave suffers pi phase change when it is reflected from a medium of higher refractive index than that of the medium of incidence.

ehild
 

What is the "Double Slit with Reflections" experiment?

The double slit with reflections experiment is a classic physics experiment that demonstrates the wave nature of light. It involves directing a beam of light through two parallel slits and observing the interference pattern that is created on a screen behind the slits.

How does the double slit with reflections experiment work?

In this experiment, a beam of light is directed towards two parallel slits, creating two coherent sources of light. As the light passes through the slits, it diffracts and interferes with itself, creating an interference pattern on a screen placed behind the slits. This pattern is caused by the constructive and destructive interference of the light waves.

What is the significance of the double slit with reflections experiment?

The double slit with reflections experiment is significant because it provides evidence for the wave nature of light. It also illustrates the concept of interference, which plays a crucial role in many other areas of science, such as optics and quantum mechanics.

What factors affect the interference pattern in the double slit with reflections experiment?

The interference pattern in this experiment can be affected by several factors, including the wavelength of light, the distance between the slits, and the distance between the slits and the screen. Additionally, reflections from the slits and the screen can also impact the interference pattern.

What applications does the double slit with reflections experiment have?

The double slit with reflections experiment has numerous applications in science and technology. It is used in optics and photonics to study the behavior of light and can also be applied to other wave phenomena, such as sound waves. Additionally, the principles of this experiment are also utilized in technologies such as holography and quantum computing.

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