Double your speed. (True/False)

  • Thread starter Thread starter FAJISTE
  • Start date Start date
  • Tags Tags
    Speed
AI Thread Summary
Doubling your driving speed results in a quadrupling of stopping time and distance due to the physics of constant deceleration. The relevant equations indicate that stopping time is directly related to the initial speed, while stopping distance is influenced by the square of that speed. Participants in the discussion express confusion over which formulas to apply but ultimately focus on the relationships between speed, time, and distance. The conversation emphasizes the importance of understanding these equations to solve the problem correctly. Overall, the key takeaway is that increased speed significantly affects both stopping time and distance.
FAJISTE
Messages
57
Reaction score
0

Homework Statement



Assume that the brakes in your car create a constant deceleration, independent of how fast you are driving. If you double your driving speed, which of the following statements are true?
Your stopping time will quadruple.
Your stopping time will not change.
Your stopping distance will double.
Your stopping time will double.
Your stopping distance will quadruple.
Your stopping distance will not change.

Homework Equations





The Attempt at a Solution



Well, mainly I'm not sure which formula to use, and I'm also confused cause I can't find one which contains speed. And I know velocity is different from that.

So maybe to start off with a formula? Thanks
 
Physics news on Phys.org
FAJISTE said:
Well, mainly I'm not sure which formula to use, and I'm also confused cause I can't find one which contains speed. And I know velocity is different from that.

So maybe to start off with a formula? Thanks

You first! :wink:

What formulas do you know? :smile:
 
Um, vf - vi = at

d = vi*t + 1/2at^2

vf^2 - vi^2 = 2ad
 
I'd use the first one of those, if I were you and from that you can set up a ratio between t1 and t2 (;
 
I'm guessing false for all of them but idno that's probably wrong
 
Yeah i still don't get this
 
If you start with the formula:

vf - vi = at

If you treat them as different cases you have:

vf1-vi1=a*t1
and
vf2-vi2=a*t2

You know the relationship between the initial velocities, try to work it out from there..
 
FAJISTE said:
Um, vf - vi = at

d = vi*t + 1/2at^2

vf^2 - vi^2 = 2ad

For stopping time you need an equation with t in it.

For stopping distance you need an equation with d in it.

Let's start with the stopping time, t … how do you think t depends on vf?
 
Well as the velocity increases, the time usually decreases, but isn't this different? Also this is due in 10 minutes lol
 
  • #10
FAJISTE said:
Well as the velocity increases, the time usually decreases, but isn't this different?

uhh? look at the equation … that's what equations are for! :smile:
 
  • #11
woo got it at the last second thanks haha
 
Back
Top