The problem involves a 1 mile long copper wire with an initial resistance of 68 ohms, and the inquiry focuses on determining the new resistance when the wire is doubled over to function as a single wire.
There is ongoing exploration of the concepts related to resistance, with various interpretations being discussed. Some participants suggest that doubling the width and halving the length affects resistance, while others reference external resources for clarification. No consensus has been reached on the correct approach or answer.
Participants are navigating through assumptions about how resistance changes with modifications to the wire's dimensions, and there is a lack of clarity on the foundational principles involved.
OK. More generally, how does resistance depend on length and cross-sectional area?dymand68 said:I know that when it is cut in half R=34 ohms
No. Read this: http://hyperphysics.phy-astr.gsu.edu/hbase/electric/resis.html#c2"dymand68 said:inverse square rule?
That's right. As that site explains, the resistance is inversely proportional to the cross-sectional area (which gives one factor 1/2) and directly proportional to the length (which gives a second factor of 1/2).dymand68 said:the correct answer is 17 ohms...double width, 1/2 length =1/4 resistance?