Doubling the frequency of a quantum harmonic oscillator

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SUMMARY

The discussion centers on the quantum mechanics of a harmonic oscillator where the classical frequency doubles from w to w' = 2w. The participant seeks to determine the probability of measuring the energy value h'w/2 immediately after this frequency change, while the wavefunction remains unchanged. The relevant equations include the Hamiltonian H = (a'*a + 1/2)h'w and energy levels En = (n+1/2)h'w for the harmonic oscillator. The conclusion drawn is that the probability of measuring the original energy value h'w/2 is zero due to the alteration in the energy eigenstates following the frequency change.

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  • Proficiency in using creation and annihilation operators (a' and a)
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Homework Statement



A particle is in the ground state of a harmonic oscillator with classical frequency w. Suddenly the classical frequency doubles, w -> w' = 2w without initially changing the wavefunction. Instantaneously afterwards, what is the probability that a measurement of energy would still return the value h'w/2? (where h' denotes h-bar).

Homework Equations



Earlier in the question, I had to show that H = (a'*a + 1/2)h'w where a' and a are the creating and annihilation operators, respectively. Also, En = (n+1/2)h'w for a harmonic oscillator.

The Attempt at a Solution



I'm honestly not at all sure how to approach this; my instinct would be to say that it has a probability of 0, but that seems unlikely.
 
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I know that the wavefunction is psi_n = (1/sqrt(2^n * n!))*(a'^n)*psi_0, so a measurement of energy after the frequency has changed would be En' = (n+1/2)h'w' = (n+1/2)(2)h'w. Any help would be greatly appreciated; thank you!
 

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