The main aim of turning on/off an scr is to disconnect source from load. I read in dv/dt protection of scr using snubber circuit, the scr may turn on when dV/dt is very high as the charging current i=cdV/dt will be high enough to turn on scr. So we are using a snubber circuit to divert this high current. With high switching currents, the capacitor(shown in the attachment) will be having low impedance and hence it give an easy path for current and hence protect the scr. My doubt is this: While using the above protection circuit, even when the scr is off the source voltage will be connected to the load(Always!) right? Then there will be no use of using the scr. And i have seen a similar problem while learning series operation of scrs. There to eliminate problems we connect resistances in parallel with scr??? I don't understand. I am confused. I hope my question is clear.