Berkeman is right you haven't given us much to go on
Mohr circles can be used for the angular variation of
Moments/Products of Inertia
Strain at a point
Stress at a point
I am guessing that you are studying the last one so here is the procedure in the attached sketches.
Fig 1
Shows a small square under X axis tension (reckoned +ve) and Y axis compression (reckoned negative).
I have shown in red a plane cutting the square. The normal to this plane makes an angle [tex]\theta[/tex]1 with the X axis.
The stresses on this plane are required.
Fig 2
Draw rectangular axes for shear (Ss) and normal (Sn ) stresses.
Plot the point A (Sx , 0) corresponding to the X axis tension with zero shear.
Plot the point B (-Sy , 0) corresponding to the Y axis compression with zero shear. Note that this is negative.
Fig 3
Find the centre, C of the Mohr circle halfway between A and B.
Note this will rarely be the origin.
Fig 4
Draw the Mohr circle with centre C and radius CA or CB.
Fig 5
Draw the diameter through C at angle twice [tex]\theta[/tex]1 to the Sn axis, meetiong the circle at D and E.
Read off the shear and normal stresses for D. These are the required values.
Fig 6
As you requested I have plotted a different angle, [tex]\theta[/tex]2 , corresponding to a different angle of cutting plane on the same diagram.
The circle, of course, shows all such angles.
go well