fishingspree2
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Homework Statement
We have a sheet of charge, which is infinite in the x direction and has width d in the y direction.
Find E field at a height h above the center line of the sheet. The sheet has λs surface charge density.
My attempt:
We know that the E field for an infinite wire is λl / 2πrε in the radial direction.
We treat the semi-infinite sheet as if it was composed of infinite wires with width dy and λl = λs dy
Therefore,
dE for an infinite wire = (λs dy) / (2πrε) in r direction, where r is a unit vector from the wire to the observation point.
For each infinite wire, vector r = -y y + h z where y and z are the unit vectors.
Therefore, r = ( -y y + h z ) / sqrt(y2 + h2)
and
dE = [(λs dy) / (2πr2ε)] ( -y y + h z )
= [(λs dy) / (2πε(y2 + h2)] ( -y y + h z )
From symetry reasons I know that the E field wield be in the z direction, so I discard the y part:
dE = [(λs dy) / (2πε(y2 + h2)] (h z )
I integrate [(λs dy) / (2πε(y2 + h2)] (h z ) from y = -d/2 to d/2
= (λs h z) / (2πε) integral of (dy / y2 + h2)
completing the integration I get:
(λs h z) / (πε) ) atan(d/2h)
but the h factor shouldn't be there because it shouldn't depend on the height of the observation point.
Where is the mistake?
(I have done it another way here https://www.physicsforums.com/showpost.php?p=4279144&postcount=7 but I don't see where is the mistake)