E-Field in Hollow Polarized Dielectric

AI Thread Summary
The discussion centers on determining the electric field intensity at the center of a spherical cavity within a polarized dielectric. The user has identified the challenge of dealing with a non-uniform charge distribution due to polarization, leading to varying surface charge densities. A suggestion was made to use a sine function for integration to account for the sinusoidal transition of charge around the sphere. Clarification was provided that surface charge does exist, with positive charges at the top and negative at the bottom of the sphere. The original poster plans to share the solution once found, highlighting the ongoing interest in solving this complex problem.
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Homework Statement


Determine the electric field intensity at the center of a small spherical cavity cut out of a large block of dielectric in which a polarization P exists.

The Attempt at a Solution


charge densitysurface = P(dot)n --> charge densitysurface = P(dot)r

This is about as far as I've gotten... My problem is I've never dealt with a non-uniform charge distribution before. My first goal was to find the surface charge around the sphere, but the polarization makes it such that it's non-uniform. I've assumed that the dielectric is polarized in the positive-z direction, which puts a concentration of negative charges at the top of the sphere and a concentration of positive charges at the bottom. My professor recommended using a sin() function to integrate over the sphere (positive->neutral->negative->neutral->repeat), but I don't really know how to fit this into a surface integral. Any thoughts?

Thanks,
Spencer
 
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The material is a dialectric. I don't think it's to be supposed that there is surface charge.
 
There actually i s surface charge - picture a surface of thin dielectric in the xy-plane. If you polarize the whole thing with an e-field in the z-direction, the dipoles at the top of the plane will have their positive charges pointing up (giving a positive surface charge). Likewise, the bottom will have a negative surface charge. This case is tricky, because it's a sphere, so there's a smooth transition around the surface that goes sinusoidally. The professor has actually solved the problem since I first posted the problem, so I'll post a solution later for anybody who's interested.
 
I'd love to see that solution.
 
Haha - so, I've graduated since I originally posted this problem a couple years ago, but I actually just pulled out a box of old schoolwork to sort through. If I can find the solution, I'll post it.
 
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