How to Integrate 1-cos(t)dt and Prove the Resulting Derivative

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SUMMARY

The discussion focuses on integrating the function 1-cos(t) with respect to t and proving the derivative of the resulting integral. The user seeks assistance with evaluating the integral g(x) = ∫[π,x] (1-cos(t)) dt. It is established that the derivative g'(x) equals 1-cos(x) based on the Fundamental Theorem of Calculus. The integral can be separated into two parts: I = I₁ + I₂, where I₁ = ∫1 dt and I₂ = -∫cos(t) dt, leading to the conclusion that the derivative of -sin(t) is essential for the proof.

PREREQUISITES
  • Understanding of the Fundamental Theorem of Calculus
  • Knowledge of basic integral calculus, specifically integrating trigonometric functions
  • Familiarity with the properties of definite integrals
  • Ability to differentiate basic trigonometric functions
NEXT STEPS
  • Review the Fundamental Theorem of Calculus and its applications
  • Practice integrating trigonometric functions, focusing on sin(t) and cos(t)
  • Study the properties of definite integrals and their implications
  • Learn techniques for differentiating composite functions involving trigonometric identities
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Students studying calculus, particularly those needing assistance with integration and differentiation of trigonometric functions, as well as educators looking for examples of applying the Fundamental Theorem of Calculus.

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Homework Statement



it's been a long summer and i forgot everything.
i need help integrating 1-cos(t)dt

evaluate g(x) = [\pi,x]integral (1-cos(t))dt

i know by pt2 of fund. thm of calc that g' (x) = 1-cos(x)
but i can't remember how to evaluate the integral and then differentiate to prove my answer.\
I should just know the integral of 1-cosx but I'm retarded and forgot what to do.
any help?
 
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Well you know that by the properties of integrals, you can treat it as two integrals
I=I_1+I_2=\left(\int 1dt\right)+\left(-\int\cos{t}dt\right)
Do you know these integrals? What is the derivative of -\sin{t}?
 

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