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Easy stuff, i'm just retarded

  1. Aug 25, 2009 #1
    1. The problem statement, all variables and given/known data

    it's been a long summer and i forgot everything.
    i need help integrating 1-cos(t)dt

    evaluate g(x) = [[tex]\pi[/tex],x]integral (1-cos(t))dt

    i know by pt2 of fund. thm of calc that g' (x) = 1-cos(x)
    but i can't remember how to evaluate the integral and then differentiate to prove my answer.\
    I should just know the integral of 1-cosx but i'm retarded and forgot what to do.
    any help?
  2. jcsd
  3. Aug 25, 2009 #2
    Well you know that by the properties of integrals, you can treat it as two integrals
    [tex]I=I_1+I_2=\left(\int 1dt\right)+\left(-\int\cos{t}dt\right)[/tex]
    Do you know these integrals? What is the derivative of [itex]-\sin{t}[/itex]?
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