- #1

nallur

- 6

- 1

Any answers will be much appreciated!

The following is a deep conceptual issue I have. The diagram is a bit crude but will suffice I think.

Note: Had drawn the circular 'electric field' at the time, to just help myself over my confusion. Feel free to ignore it.

As per Ohm's law V = IR. In the above scenario there is greater resistance at point 1 then there is at point 2 (as shown on the diagram). The charges (q1 and q2) and so the current flowing through both points are the same.

Voltage is defined as the strength of an electric field to cause current flow. And current flow is nothing but the movement of charges i.e. Movement of electrons.

So following on, this means that according to Ohm's law of V = IR, there is a greater voltage at point 1 then there is at point 2. Therefore voltage will 'flow' from point 1 to point 2 i.e., From high to low.

This is where my issue arises. With there being greater resistance for the electrons to flow from point 1 how is it that the electrons will go from point 1 to point 2? Shouldn't it be the other way around. I don't conceptually understand how the greater resistance in this way causes voltage flow and so current flow from point 1 to 2. From my definition of voltage given, the greater resistance at point 1 would actually make it harder for the current to flow from point 1 to 2. Conversely the lower resistance at point 2 would make it easier for the current to flow from point 2 to 1.

Yet, and as per Ohm's law, voltage is greater at point 1 so current somehow flows down?

It is kind of a question within another question, so had to explain myself a bit. I am really not knowledgeable in electrical phenomena, so this may very well be a basic matter that I don't know!